// This program computes a(n) = a(n-1) + 3n for n = 0..10, a(0) = 1;
// The output is a(n) for n = 0..10.


#include <stdio.h>

int rec (int);
int mult3 (int);


int main ()

{
   int n = 0;
   int a_n;


   while (n <= 10) {

      a_n = rec (n);

      printf ("%4d   0x%08x\n", a_n, a_n);

      n++;
   }
}


int rec (int i)

{
   int ret;
   int rec_val;
   int i3;

   if (i == 0)
      ret = 1;

   else {
      rec_val = rec (i - 1);

      i3 = mult3 (i);

      ret = rec_val + i3;
   }

   return ret;
}


int mult3 (int z)

{
   int ret;

   ret = z;
   ret += z;
   ret += z;

   return ret;
}